Originally posted by wimNP
I have a problem with the following task.Day 4 combos – Task 6
How many combos are there in the range of QJo+?
IMO there is just one hand: OJo.
The spoiler gives an other answer.Because:
First:Day 4 combos – Task 1
As usual, let's start with a recap from the previous day
![]()
How many KTo+ are possible?This notation (KTo+) gives the highest ranked card first and the lowest kicker next. In each following hand the high card will remain the same but the kicker will be one rank higher. This repeats itself till the kicker reaches the value of the high card: e.g. AJo+ = AJo AQo AKo.
The notation KTo+ describes off-suited hands King-high Ten up to and with KQoSecond:
Day 3 combos – Task 16
Let's try another range
![]()
How many combos of 67o+ are possible?This notation (67o) gives the lowest ranked card first and its higher adjacent neighbour second. In each following hand the first card will be one rank higher than the one in the previous hand. The second card must be one rank higher than the one in the preceding hand. This repeats itself until the second card is an ace. However: in writing the given sequence out the higher card will come first. E.g. JQo = QJo KQo AKo.
The notation 67o describes off-suited contecting hands from 76 up to and with AK.
if the cards are direct neighbours the + means that you will count up both cards:
45s+ (or 54s+) => 45s, 56s, 67s....
if the cards are not direct neighbours, the + indicates that you only count the smaller card up until it is one less than the bigger card.
95s+ (or 59s+) => 95s, 96s, 97s and 98s
Yes, this is counter intuitive, but we gotta live with this - it's the poker industry standard and we are not going to confuse you by changing it.

= got it right in the first try
= got it wrong in the first try