PokerStrategist Mastermind Challenge - Question 2
We have one deck and we want to take 6 cards in order to form 3 pairs that comply with these conditions:
The first 2 cards (A) have more equity than the second pair (B)
The second 2 cards (B) have more equity than the third pair (C)
The third 2 cards (C) have more equity than the first pair (A)
What cards could A, B and C be?
Note: there can be several combinations, but you will have to show with 3 equilab screenshots that the 3 conditions are met.
Besides, we all play with the same deck so the cards that have been used in the previous answers (correct or incorrect) will not be valid to use anymore.
Since equilab does not specify suits in pairs, we can use them 2 times. For example:
10 10 is better than
A-clubs K- clubs
In this case, the A-clubs and K-clubs cannot be used anymore, but we still have two 10 in the deck that could be used again in a pair, but also in two separate combinations (A10, K10...)
ANSWER AS FAST AS POSSIBLE OR YOU MIGHT RUN OUT OF CARDS!
Post your answers below
