Hi
I am trying to get a good answer for this problem :
3handed game. Bu open and SB only 3bets 15% and fold everything else.BB 3bets 10%.
How often is BU facing a 3bet ?
Notifications
Clear all
2 replies
P(BU faces a 3bet) = (sb 3bets) OR (SB folds AND BB 3bets)
0.15+ (0.85*0.1) = 0.235 = 23.5%
I hope I got it right ♦ I has been some time since I had probability calculations in school.