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Sklansky's Theorem - Results Oriented?

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metza
Joined: 28.01.2012

So for anyone who doesn't already know Sklansky's theory goes that when you play different to how you would if you could see your opponents cards you make a mistake, and when they play differently, they make a mistake.

What if you were up against an opponent who starts going all in every hand? A few hands later you have KK, and call, and he turns over AA. According to Sklansky, this call would be a mistake. But clearly if you look at it on a logical level, folding KK to an opponent who is shoving every hand is definitely a mistake.

Does this mean Sklansky's theorem is results oriented?


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Tomaloc
Joined: 17.01.2011

that's why galfond improved on that with g-bucks

on g-bucks you take your entire range vs villain's entire range. now that's theoretically awesome


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MadInAVacuum
Joined: 14.08.2010

You are missing this part:

... if you could see all your opponents' cards ...


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Hi guys, this is a common critique. To sklansky's credit the idea which continues to hold true is that we should make decisions that are most likely to be the same ones we'd make if we could see our opponents cards. When we do this we must consider our opponents entire range.


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metza
Joined: 28.01.2012

Originally posted by Tomaloc
that's why galfond improved on that with g-bucks

on g-bucks you take your entire range vs villain's entire range. now that's theoretically awesome

Thanks! I like Galfond as a player, will definitely look into this.


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