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6max bubble: 2 shorts vs bigstack

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julito23
Joined: 24.08.2011

Microgaming - 0|100/200 NL (6 max) - Holdem - 3 players
Hand converted by PokerTracker 4

BTN: 7.8 BB (VPIP: 14.76, PFR: 11.23, 3Bet Preflop: 3.79, Hands: 1,296)
SB: 28.45 BB (VPIP: 24.65, PFR: 22.02, 3Bet Preflop: 9.61, Hands: 12,033)
Hero (BB): 8.75 BB

SB posts SB 0.5 BB, Hero posts BB 1 BB

Pre Flop: (pot: 1.5 BB) Hero has 3♣ K♠

fold, SB raises to 28.45 BB and is all-in, fold

SB is a decent reg.

Playing around with HRC I came across the following. In this spot SB has an any 2 shove and we call 11%, which is 66+,A8s+,ATo+,KTs+ and KQ, which is a bit tighter than what my initial guess was.

Then I decided to decrease SB's stack to around 15BB. Then he still has any 2, however, we call much much wider, up to 25.6%, 55+ A2s+ A4o+ K7s+ K9o+ Q9s+ QTo+ JTs.

Why are we so much less risk averse if SB's stack is not as big?

My guess is that if we win in the first case, we become midstack, while if we win on the second we become the bigstack, which will put us on a lot more +EV situations than in the first case.

However, future EV is not taken into account in a regular Nash equilibrium calculation. Therefore the only thing left is the fact that we are favourite simply because we have more chips.

My question is:

Is my hypothesis reasonable? Would you add any other reason that could be causing this effect?


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2 replies

you will gain more of the equity pool by winning a larger % of the total chips in play.

you basically removed 13BBs off the table, so when you doubled up in the second scenario you gained a much larger proportion of total chips = higher EV value = call wider.


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julito23
Joined: 24.08.2011

Ok, it is kind of the same as my idea but expressed in a much more elegant way.

Thanks.


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